summ = 0
for a in range(3,1001):
if a%2==0:
r=a*(a-2)
else:
r = a*(a-1)
summ += r
print(summ)
Project Euler Problem 120
Go here for question
summ = 0
for a in range(3,1001):
if a%2==0:
r=a*(a-2)
else:
r = a*(a-1)
summ += r
print(summ)